Random with min and max

Posted on August 9th, 2008 in VB. NET Functions by Terp

Simple as this:


Private Function RandomNumberAsString(ByVal Min As Int32, ByVal Max As Int32) As String
Return (New Random).Next(Min, Max).ToString
End Function

Example:
msgbox(RandomNumberAsString(2, 99))

Will open a dialog with a number between 2 and 99

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